How to find record with xml data containing value...

Hello all,
SQL2005
I am newbe in XPath and XQuery
I have to find in table with xml field all records where value of attribute
contains string (e.g person name)
drop table dbo.bbb;
create table dbo.bbb(
p1 int not null identity,
p2 xml,
primary key(p1) );
insert into dbo.bbb values
('<root><item werte="d1"/><item werte="a2"/></root>');
insert into dbo.bbb values
('<root><item werte="b1"/><item werte="b2"/></root>');
select *
from dbo.bbb
where p2.value('contains((/root/item/@.werte)[1],"a")','bit') = 1
this query give me records with @.werte containing "a" but only if it is in
first item,
I have to find records with @.werte containing "a" regardless of item
position.
Can anybody help me write this query?
Regards
Yaro
OK, I know
select *
from dbo.bbb
where
p2.exist('/root/item/@.werte[contains(.,"a")]') = 1
Yaro
Uytkownik "Yaro" <yarok_delthisdes_@.op.pl> napisa w wiadomoci
news:e12vcm$nq4$1@.83.238.170.160...
> Hello all,
> SQL2005
> I am newbe in XPath and XQuery
> I have to find in table with xml field all records where value of
> attribute contains string (e.g person name)
> drop table dbo.bbb;
> create table dbo.bbb(
> p1 int not null identity,
> p2 xml,
> primary key(p1) );
> insert into dbo.bbb values
> ('<root><item werte="d1"/><item werte="a2"/></root>');
> insert into dbo.bbb values
> ('<root><item werte="b1"/><item werte="b2"/></root>');
> select *
> from dbo.bbb
> where p2.value('contains((/root/item/@.werte)[1],"a")','bit') = 1
> this query give me records with @.werte containing "a" but only if it is
> in first item,
> I have to find records with @.werte containing "a" regardless of item
> position.
> Can anybody help me write this query?
> Regards
> Yaro